-50x^2+300x+50=0

Solution for -50x^2+300x+50=0 equation:

-50x^2+300x+50=0

a = -50; b = 300; c = +50;
Δ = b2-4ac
Δ = 3002-4·(-50)·50
Δ = 100000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{100000}=\sqrt{10000*10}=\sqrt{10000}*\sqrt{10}=100\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(300)-100\sqrt{10}}{2*-50}=\frac{-300-100\sqrt{10}}{-100}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(300)+100\sqrt{10}}{2*-50}=\frac{-300+100\sqrt{10}}{-100}
$